250x^2-245+49=x

Solution for 250x^2-245+49=x equation:

250x^2-245+49=x

We move all terms to the left:

250x^2-245+49-(x)=0

We add all the numbers together, and all the variables

250x^2-1x-196=0

a = 250; b = -1; c = -196;
Δ = b2-4ac
Δ = -12-4·250·(-196)
Δ = 196001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{196001}}{2*250}=\frac{1-\sqrt{196001}}{500}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{196001}}{2*250}=\frac{1+\sqrt{196001}}{500}
$